AB = 12 CM
BC = 10 CM
CD = 4 CM
DA = 6 CM
makasih banyak
Keliling
= AB + BC + CD + AD
= 12 + 10 + 4 + 6
= 22 + 10
= 32 cm
[tex] \: [/tex]
Luas
= ½ × (AB + DC) × AD
= ½ × (12 + 4) × 6
= 16 × 3
= 48 cm²
Jawaban:
Luas = 60cm²
Keliling = 48cm
Penjelasan dengan langkah-langkah:
[tex]bangun \: 1 = persegi \: panjang \: \\ p = 6cm \: \: \: \: l = 4cm \\ luas = p \times l \\ = 6 \times 4 \\ = 24 {cm}^{2} \\ keliling = 2 \times (p + l) \\ = 2 \times (6 + 4) \\ = 2 \times 10 \\ = 20cm \\ bangun \: 2 = segitiga \: siku - siku \\ t (sisi \: \: a)= 6cm \\ a (sisi \: \: b)= 12cm \\ sisi \: miring(sisi \: \: c) = 10cm \\ luas = \frac{1}{2} \times a \times t \\ = \frac{1}{2} \times 12 \times 6 \\ = \frac{1}{2} \times 72 \\ = 36 {cm}^{2} \\ keliling = a + b + c \\ = 6 + 12 + 10 \\ = 28cm \\ luas \: seluruhnya = luas \: bangun \: 1 + \: luas \: bangun \: 2 \\ = 24 + 36 \\ = 60 {cm}^{2} \\ keliling \: seluruhnya = keliling \: bangun \: 1 + keliling \: bangun \: 2 \\ = 20 + 28 \\ = 48cm[/tex]
